Jawaban:
9. (sy anggap lim x->5)
tes limit:
[tex] \frac{3 {(5)}^{2} - 14(5) - 5 }{ {5}^{2} - 25 } = \frac{0}{0} [/tex]
maka bisa dgn cara l'Hospitâl
[tex] = \frac{d(3 {x}^{2} - 14x - 5) }{d( {x}^{2} - 25) } [/tex]
[tex] = \frac{6x - 14}{2x} [/tex]
tes limit:
[tex] \frac{6(5) - 14}{2(5)} = \frac{8}{5} [/tex]
krn hasil bukan 0/0 atau ~/~, maka hasil = 8/5
10.
tes limit:
[tex] \frac{2 - \sqrt{2(0) + 4} }{0} = \frac{0}{0} [/tex]
cara l'Hospitâl
[tex] = \frac{d(2 - ({2x + 4})^{ \frac{1}{2} }) }{dx} [/tex]
[tex] = \frac{ - \frac{1}{2} {(2x + 4)}^{ - \frac{1}{2} }(2) }{1} [/tex]
[tex] = - \frac{1}{ \sqrt{2x + 4} } [/tex]
tes limit:
[tex] = - \frac{1}{ \sqrt{2(0) + 4} } [/tex]
[tex] = - \frac{1}{2} [/tex]
krn hasil bukan 0/0 atau ~/~, maka hasil = -½
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